Is 6997 a prime number? What are the divisors of 6997?

## Is 6997 a prime number?

Yes, 6997 is a prime number.

Indeed, the definition of a prime numbers is to have only two distinct positive divisors, 1 and itself. A number is a divisor of another number when the remainder of Euclid’s division of the second one by the first one is zero. Concerning the number 6997, the only two divisors are 1 and 6997. Therefore 6997 is a prime number.

As a consequence, 6997 is only a multiple of 1 and 6997.

Since 6997 is a prime number, 6997 is also a deficient number, that is to say 6997 is a natural integer that is strictly larger than the sum of its proper divisors, i.e., the divisors of 6997 without 6997 itself (that is 1, by definition!).

## Parity of 6997

6997 is an odd number, because it is not evenly divisible by 2.

## Is 6997 a perfect square number?

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 6997 is about 83.648.

Thus, the square root of 6997 is not an integer, and therefore 6997 is not a square number.

Anyway, 6997 is a prime number, and a prime number cannot be a perfect square.

## What is the square number of 6997?

The square of a number (here 6997) is the result of the product of this number (6997) by itself (i.e., 6997 × 6997); the square of 6997 is sometimes called "raising 6997 to the power 2", or "6997 squared".

The square of 6997 is 48 958 009 because 6997 × 6997 = 69972 = 48 958 009.

As a consequence, 6997 is the square root of 48 958 009.

## Number of digits of 6997

6997 is a number with 4 digits.

## What are the multiples of 6997?

The multiples of 6997 are all integers evenly divisible by 6997, that is all numbers such that the remainder of the division by 6997 is zero. There are infinitely many multiples of 6997. The smallest multiples of 6997 are:

• 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 6997 too, since 0 × 6997 = 0
• 6997: indeed, 6997 is a multiple of itself, since 6997 is evenly divisible by 6997 (we have 6997 / 6997 = 1, so the remainder of this division is indeed zero)
• 13 994: indeed, 13 994 = 6997 × 2
• 20 991: indeed, 20 991 = 6997 × 3
• 27 988: indeed, 27 988 = 6997 × 4
• 34 985: indeed, 34 985 = 6997 × 5
• etc.

## Nearest numbers from 6997

Find out whether some integer is a prime number