It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 71 242 016 is not a prime number.
For example, 71 242 016 can be divided by 2: 71 242 016 / 2 = 35 621 008.
For 71 242 016 to be a prime number, it would have been required that 71 242 016 has only two divisors, i.e., itself and 1.
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71 242 016 is an even number, because it is evenly divisible by 2: 71 242 016 / 2 = 35 621 008.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 71 242 016 is about 8 440.499.
Thus, the square root of 71 242 016 is not an integer, and therefore 71 242 016 is not a square number.
The square of a number (here 71 242 016) is the result of the product of this number (71 242 016) by itself (i.e., 71 242 016 × 71 242 016); the square of 71 242 016 is sometimes called "raising 71 242 016 to the power 2", or "71 242 016 squared".
The square of 71 242 016 is 5 075 424 843 744 256 because 71 242 016 × 71 242 016 = 71 242 0162 = 5 075 424 843 744 256.
As a consequence, 71 242 016 is the square root of 5 075 424 843 744 256.
71 242 016 is a number with 8 digits.
The multiples of 71 242 016 are all integers evenly divisible by 71 242 016, that is all numbers such that the remainder of the division by 71 242 016 is zero. There are infinitely many multiples of 71 242 016. The smallest multiples of 71 242 016 are: