It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 7 136 638 is not a prime number.
For example, 7 136 638 can be divided by 2: 7 136 638 / 2 = 3 568 319.
For 7 136 638 to be a prime number, it would have been required that 7 136 638 has only two divisors, i.e., itself and 1.
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7 136 638 is an even number, because it is evenly divisible by 2: 7 136 638 / 2 = 3 568 319.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 7 136 638 is about 2 671.449.
Thus, the square root of 7 136 638 is not an integer, and therefore 7 136 638 is not a square number.
The square of a number (here 7 136 638) is the result of the product of this number (7 136 638) by itself (i.e., 7 136 638 × 7 136 638); the square of 7 136 638 is sometimes called "raising 7 136 638 to the power 2", or "7 136 638 squared".
The square of 7 136 638 is 50 931 601 943 044 because 7 136 638 × 7 136 638 = 7 136 6382 = 50 931 601 943 044.
As a consequence, 7 136 638 is the square root of 50 931 601 943 044.
The multiples of 7 136 638 are all integers evenly divisible by 7 136 638, that is all numbers such that the remainder of the division by 7 136 638 is zero. There are infinitely many multiples of 7 136 638. The smallest multiples of 7 136 638 are: