It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 733 438 is not a prime number.
For example, 733 438 can be divided by 2: 733 438 / 2 = 366 719.
For 733 438 to be a prime number, it would have been required that 733 438 has only two divisors, i.e., itself and 1.
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733 438 is an even number, because it is evenly divisible by 2: 733 438 / 2 = 366 719.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 733 438 is about 856.410.
Thus, the square root of 733 438 is not an integer, and therefore 733 438 is not a square number.
The square of a number (here 733 438) is the result of the product of this number (733 438) by itself (i.e., 733 438 × 733 438); the square of 733 438 is sometimes called "raising 733 438 to the power 2", or "733 438 squared".
The square of 733 438 is 537 931 299 844 because 733 438 × 733 438 = 733 4382 = 537 931 299 844.
As a consequence, 733 438 is the square root of 537 931 299 844.
The multiples of 733 438 are all integers evenly divisible by 733 438, that is all numbers such that the remainder of the division by 733 438 is zero. There are infinitely many multiples of 733 438. The smallest multiples of 733 438 are: