It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 733 518 is not a prime number.
For example, 733 518 can be divided by 2: 733 518 / 2 = 366 759.
For 733 518 to be a prime number, it would have been required that 733 518 has only two divisors, i.e., itself and 1.
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733 518 is an even number, because it is evenly divisible by 2: 733 518 / 2 = 366 759.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 733 518 is about 856.457.
Thus, the square root of 733 518 is not an integer, and therefore 733 518 is not a square number.
The square of a number (here 733 518) is the result of the product of this number (733 518) by itself (i.e., 733 518 × 733 518); the square of 733 518 is sometimes called "raising 733 518 to the power 2", or "733 518 squared".
The square of 733 518 is 538 048 656 324 because 733 518 × 733 518 = 733 5182 = 538 048 656 324.
As a consequence, 733 518 is the square root of 538 048 656 324.
The multiples of 733 518 are all integers evenly divisible by 733 518, that is all numbers such that the remainder of the division by 733 518 is zero. There are infinitely many multiples of 733 518. The smallest multiples of 733 518 are: