Is 7840013 a prime number?

7 840 013 is an odd number, because it is not evenly divisible by 2.

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• What is an even number?

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 7 840 013 is about 2 800.002.

Thus, the square root of 7 840 013 is not an integer, and therefore 7 840 013 is not a square number.

Anyway, 7 840 013 is a prime number, and a prime number cannot be a perfect square.

The square of a number (here 7 840 013) is the result of the product of this number (7 840 013) by itself (i.e., 7 840 013 × 7 840 013); the square of 7 840 013 is sometimes called "raising 7 840 013 to the power 2", or "7 840 013 squared".

The square of 7 840 013 is 61 465 803 840 169 because 7 840 013 × 7 840 013 = 7 840 013² = 61 465 803 840 169.

As a consequence, 7 840 013 is the square root of 61 465 803 840 169.

7 840 013 is a number with 7 digits.

The multiples of 7 840 013 are all integers evenly divisible by 7 840 013, that is all numbers such that the remainder of the division by 7 840 013 is zero. There are infinitely many multiples of 7 840 013. The smallest multiples of 7 840 013 are:

• 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 7 840 013 too, since 0 × 7 840 013 = 0
• 7 840 013: indeed, 7 840 013 is a multiple of itself, since 7 840 013 is evenly divisible by 7 840 013 (we have 7 840 013 / 7 840 013 = 1, so the remainder of this division is indeed zero)
• 15 680 026: indeed, 15 680 026 = 7 840 013 × 2
• 23 520 039: indeed, 23 520 039 = 7 840 013 × 3
• 31 360 052: indeed, 31 360 052 = 7 840 013 × 4
• 39 200 065: indeed, 39 200 065 = 7 840 013 × 5
• etc.

• Preceding numbers: …7 840 011, 7 840 012
• Following numbers: 7 840 014, 7 840 015…

Nearest numbers from 7 840 013

• Preceding prime number: 7 839 961
• Following prime number: 7 840 031

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• 7 840 013 est-il un nombre premier ?