Is 7993 a prime number? What are the divisors of 7993?

## Is 7993 a prime number?

Yes, 7993 is a prime number.

Indeed, the definition of a prime numbers is to have only two distinct positive divisors, 1 and itself. A number is a divisor of another number when the remainder of Euclid’s division of the second one by the first one is zero. Concerning the number 7993, the only two divisors are 1 and 7993. Therefore 7993 is a prime number.

As a consequence, 7993 is only a multiple of 1 and 7993.

Since 7993 is a prime number, 7993 is also a deficient number, that is to say 7993 is a natural integer that is strictly larger than the sum of its proper divisors, i.e., the divisors of 7993 without 7993 itself (that is 1, by definition!).

## Parity of 7993

7993 is an odd number, because it is not evenly divisible by 2.

## Is 7993 a perfect square number?

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 7993 is about 89.404.

Thus, the square root of 7993 is not an integer, and therefore 7993 is not a square number.

Anyway, 7993 is a prime number, and a prime number cannot be a perfect square.

## What is the square number of 7993?

The square of a number (here 7993) is the result of the product of this number (7993) by itself (i.e., 7993 × 7993); the square of 7993 is sometimes called "raising 7993 to the power 2", or "7993 squared".

The square of 7993 is 63 888 049 because 7993 × 7993 = 79932 = 63 888 049.

As a consequence, 7993 is the square root of 63 888 049.

## Number of digits of 7993

7993 is a number with 4 digits.

## What are the multiples of 7993?

The multiples of 7993 are all integers evenly divisible by 7993, that is all numbers such that the remainder of the division by 7993 is zero. There are infinitely many multiples of 7993. The smallest multiples of 7993 are:

• 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 7993 too, since 0 × 7993 = 0
• 7993: indeed, 7993 is a multiple of itself, since 7993 is evenly divisible by 7993 (we have 7993 / 7993 = 1, so the remainder of this division is indeed zero)
• 15 986: indeed, 15 986 = 7993 × 2
• 23 979: indeed, 23 979 = 7993 × 3
• 31 972: indeed, 31 972 = 7993 × 4
• 39 965: indeed, 39 965 = 7993 × 5
• etc.

## Nearest numbers from 7993

Find out whether some integer is a prime number