Is 80000023 a prime number?

80 000 023 is an odd number, because it is not evenly divisible by 2.

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• What is an even number?

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 80 000 023 is about 8 944.273.

Thus, the square root of 80 000 023 is not an integer, and therefore 80 000 023 is not a square number.

Anyway, 80 000 023 is a prime number, and a prime number cannot be a perfect square.

The square of a number (here 80 000 023) is the result of the product of this number (80 000 023) by itself (i.e., 80 000 023 × 80 000 023); the square of 80 000 023 is sometimes called "raising 80 000 023 to the power 2", or "80 000 023 squared".

The square of 80 000 023 is 6 400 003 680 000 529 because 80 000 023 × 80 000 023 = 80 000 023² = 6 400 003 680 000 529.

As a consequence, 80 000 023 is the square root of 6 400 003 680 000 529.

80 000 023 is a number with 8 digits.

The multiples of 80 000 023 are all integers evenly divisible by 80 000 023, that is all numbers such that the remainder of the division by 80 000 023 is zero. There are infinitely many multiples of 80 000 023. The smallest multiples of 80 000 023 are:

• 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 80 000 023 too, since 0 × 80 000 023 = 0
• 80 000 023: indeed, 80 000 023 is a multiple of itself, since 80 000 023 is evenly divisible by 80 000 023 (we have 80 000 023 / 80 000 023 = 1, so the remainder of this division is indeed zero)
• 160 000 046: indeed, 160 000 046 = 80 000 023 × 2
• 240 000 069: indeed, 240 000 069 = 80 000 023 × 3
• 320 000 092: indeed, 320 000 092 = 80 000 023 × 4
• 400 000 115: indeed, 400 000 115 = 80 000 023 × 5
• etc.

• Preceding numbers: …80 000 021, 80 000 022
• Following numbers: 80 000 024, 80 000 025…

Nearest numbers from 80 000 023

• Preceding prime number: 79 999 987
• Following prime number: 80 000 027

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• 80 000 023 est-il un nombre premier ?