It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 80 013 022 is not a prime number.
For example, 80 013 022 can be divided by 2: 80 013 022 / 2 = 40 006 511.
For 80 013 022 to be a prime number, it would have been required that 80 013 022 has only two divisors, i.e., itself and 1.
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80 013 022 is an even number, because it is evenly divisible by 2: 80 013 022 / 2 = 40 006 511.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 80 013 022 is about 8 945.000.
Thus, the square root of 80 013 022 is not an integer, and therefore 80 013 022 is not a square number.
The square of a number (here 80 013 022) is the result of the product of this number (80 013 022) by itself (i.e., 80 013 022 × 80 013 022); the square of 80 013 022 is sometimes called "raising 80 013 022 to the power 2", or "80 013 022 squared".
The square of 80 013 022 is 6 402 083 689 572 484 because 80 013 022 × 80 013 022 = 80 013 0222 = 6 402 083 689 572 484.
As a consequence, 80 013 022 is the square root of 6 402 083 689 572 484.
80 013 022 is a number with 8 digits.
The multiples of 80 013 022 are all integers evenly divisible by 80 013 022, that is all numbers such that the remainder of the division by 80 013 022 is zero. There are infinitely many multiples of 80 013 022. The smallest multiples of 80 013 022 are: