Is 80023 a prime number?

80 023 is an odd number, because it is not evenly divisible by 2.

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• What is an even number?

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 80 023 is about 282.883.

Thus, the square root of 80 023 is not an integer, and therefore 80 023 is not a square number.

The square of a number (here 80 023) is the result of the product of this number (80 023) by itself (i.e., 80 023 × 80 023); the square of 80 023 is sometimes called "raising 80 023 to the power 2", or "80 023 squared".

The square of 80 023 is 6 403 680 529 because 80 023 × 80 023 = 80 023² = 6 403 680 529.

As a consequence, 80 023 is the square root of 6 403 680 529.

80 023 is a number with 5 digits.

The multiples of 80 023 are all integers evenly divisible by 80 023, that is all numbers such that the remainder of the division by 80 023 is zero. There are infinitely many multiples of 80 023. The smallest multiples of 80 023 are:

• 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 80 023 too, since 0 × 80 023 = 0
• 80 023: indeed, 80 023 is a multiple of itself, since 80 023 is evenly divisible by 80 023 (we have 80 023 / 80 023 = 1, so the remainder of this division is indeed zero)
• 160 046: indeed, 160 046 = 80 023 × 2
• 240 069: indeed, 240 069 = 80 023 × 3
• 320 092: indeed, 320 092 = 80 023 × 4
• 400 115: indeed, 400 115 = 80 023 × 5
• etc.

• Preceding numbers: …80 021, 80 022
• Following numbers: 80 024, 80 025…

Nearest numbers from 80 023

• Preceding prime number: 80 021
• Following prime number: 80 039

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• 80 023 est-il un nombre premier ?