Is 801023 a prime number?

801 023 is an odd number, because it is not evenly divisible by 2.

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• What is an even number?

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 801 023 is about 894.999.

Thus, the square root of 801 023 is not an integer, and therefore 801 023 is not a square number.

The square of a number (here 801 023) is the result of the product of this number (801 023) by itself (i.e., 801 023 × 801 023); the square of 801 023 is sometimes called "raising 801 023 to the power 2", or "801 023 squared".

The square of 801 023 is 641 637 846 529 because 801 023 × 801 023 = 801 023² = 641 637 846 529.

As a consequence, 801 023 is the square root of 641 637 846 529.

801 023 is a number with 6 digits.

The multiples of 801 023 are all integers evenly divisible by 801 023, that is all numbers such that the remainder of the division by 801 023 is zero. There are infinitely many multiples of 801 023. The smallest multiples of 801 023 are:

• 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 801 023 too, since 0 × 801 023 = 0
• 801 023: indeed, 801 023 is a multiple of itself, since 801 023 is evenly divisible by 801 023 (we have 801 023 / 801 023 = 1, so the remainder of this division is indeed zero)
• 1 602 046: indeed, 1 602 046 = 801 023 × 2
• 2 403 069: indeed, 2 403 069 = 801 023 × 3
• 3 204 092: indeed, 3 204 092 = 801 023 × 4
• 4 005 115: indeed, 4 005 115 = 801 023 × 5
• etc.

• Preceding numbers: …801 021, 801 022
• Following numbers: 801 024, 801 025…

Nearest numbers from 801 023

• Preceding prime number: 801 019
• Following prime number: 801 037

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• 801 023 est-il un nombre premier ?