It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 8 012 023 is not a prime number.
For example, 8 012 023 can be divided by 59: 8 012 023 / 59 = 135 797.
For 8 012 023 to be a prime number, it would have been required that 8 012 023 has only two divisors, i.e., itself and 1.
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8 012 023 is an odd number, because it is not evenly divisible by 2.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 8 012 023 is about 2 830.552.
Thus, the square root of 8 012 023 is not an integer, and therefore 8 012 023 is not a square number.
The square of a number (here 8 012 023) is the result of the product of this number (8 012 023) by itself (i.e., 8 012 023 × 8 012 023); the square of 8 012 023 is sometimes called "raising 8 012 023 to the power 2", or "8 012 023 squared".
The square of 8 012 023 is 64 192 512 552 529 because 8 012 023 × 8 012 023 = 8 012 0232 = 64 192 512 552 529.
As a consequence, 8 012 023 is the square root of 64 192 512 552 529.
The multiples of 8 012 023 are all integers evenly divisible by 8 012 023, that is all numbers such that the remainder of the division by 8 012 023 is zero. There are infinitely many multiples of 8 012 023. The smallest multiples of 8 012 023 are: