It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 8 015 113 is not a prime number.
For example, 8 015 113 can be divided by 811: 8 015 113 / 811 = 9 883.
For 8 015 113 to be a prime number, it would have been required that 8 015 113 has only two divisors, i.e., itself and 1.
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8 015 113 is an odd number, because it is not evenly divisible by 2.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 8 015 113 is about 2 831.097.
Thus, the square root of 8 015 113 is not an integer, and therefore 8 015 113 is not a square number.
The square of a number (here 8 015 113) is the result of the product of this number (8 015 113) by itself (i.e., 8 015 113 × 8 015 113); the square of 8 015 113 is sometimes called "raising 8 015 113 to the power 2", or "8 015 113 squared".
The square of 8 015 113 is 64 242 036 402 769 because 8 015 113 × 8 015 113 = 8 015 1132 = 64 242 036 402 769.
As a consequence, 8 015 113 is the square root of 64 242 036 402 769.
The multiples of 8 015 113 are all integers evenly divisible by 8 015 113, that is all numbers such that the remainder of the division by 8 015 113 is zero. There are infinitely many multiples of 8 015 113. The smallest multiples of 8 015 113 are: