It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 802 498 is not a prime number.
For example, 802 498 can be divided by 2: 802 498 / 2 = 401 249.
For 802 498 to be a prime number, it would have been required that 802 498 has only two divisors, i.e., itself and 1.
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802 498 is an even number, because it is evenly divisible by 2: 802 498 / 2 = 401 249.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 802 498 is about 895.823.
Thus, the square root of 802 498 is not an integer, and therefore 802 498 is not a square number.
The square of a number (here 802 498) is the result of the product of this number (802 498) by itself (i.e., 802 498 × 802 498); the square of 802 498 is sometimes called "raising 802 498 to the power 2", or "802 498 squared".
The square of 802 498 is 644 003 040 004 because 802 498 × 802 498 = 802 4982 = 644 003 040 004.
As a consequence, 802 498 is the square root of 644 003 040 004.
The multiples of 802 498 are all integers evenly divisible by 802 498, that is all numbers such that the remainder of the division by 802 498 is zero. There are infinitely many multiples of 802 498. The smallest multiples of 802 498 are: