It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 8 128 is not a prime number.
For example, 8 128 can be divided by 2: 8 128 / 2 = 4 064.
For 8 128 to be a prime number, it would have been required that 8 128 has only two divisors, i.e., itself and 1.
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Yes, 8 128 is a perfect number, that is to day 8 128 equals the sum of its proper positive divisors, i.e., the sum of its divisors excluding 8 128 itself.
Indeed, 8128 = 1 + 2 + 4 + 8 + 16 + 32 + 64 + 127 + 254 + 508 + 1 016 + 2 032 + 4 064.
Note that perfect numbers are very rare: there are only 4 perfect numbers smaller than 1 000 000, viz., 6, 28, 496 and 8 128. Then, the next perfect number is already 33 550 336!
8 128 is an even number, because it is evenly divisible by 2: 8 128 / 2 = 4 064.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 8 128 is about 90.155.
Thus, the square root of 8 128 is not an integer, and therefore 8 128 is not a square number.
The square of a number (here 8 128) is the result of the product of this number (8 128) by itself (i.e., 8 128 × 8 128); the square of 8 128 is sometimes called "raising 8 128 to the power 2", or "8 128 squared".
The square of 8 128 is 66 064 384 because 8 128 × 8 128 = 8 1282 = 66 064 384.
As a consequence, 8 128 is the square root of 66 064 384.
The multiples of 8 128 are all integers evenly divisible by 8 128, that is all numbers such that the remainder of the division by 8 128 is zero. There are infinitely many multiples of 8 128. The smallest multiples of 8 128 are: