Is 823001 a prime number?

823 001 is an odd number, because it is not evenly divisible by 2.

Find out more:

• What is an even number?

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 823 001 is about 907.194.

Thus, the square root of 823 001 is not an integer, and therefore 823 001 is not a square number.

Anyway, 823 001 is a prime number, and a prime number cannot be a perfect square.

The square of a number (here 823 001) is the result of the product of this number (823 001) by itself (i.e., 823 001 × 823 001); the square of 823 001 is sometimes called "raising 823 001 to the power 2", or "823 001 squared".

The square of 823 001 is 677 330 646 001 because 823 001 × 823 001 = 823 001² = 677 330 646 001.

As a consequence, 823 001 is the square root of 677 330 646 001.

823 001 is a number with 6 digits.

The multiples of 823 001 are all integers evenly divisible by 823 001, that is all numbers such that the remainder of the division by 823 001 is zero. There are infinitely many multiples of 823 001. The smallest multiples of 823 001 are:

• 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 823 001 too, since 0 × 823 001 = 0
• 823 001: indeed, 823 001 is a multiple of itself, since 823 001 is evenly divisible by 823 001 (we have 823 001 / 823 001 = 1, so the remainder of this division is indeed zero)
• 1 646 002: indeed, 1 646 002 = 823 001 × 2
• 2 469 003: indeed, 2 469 003 = 823 001 × 3
• 3 292 004: indeed, 3 292 004 = 823 001 × 4
• 4 115 005: indeed, 4 115 005 = 823 001 × 5
• etc.

• Preceding numbers: …822 999, 823 000
• Following numbers: 823 002, 823 003…

Nearest numbers from 823 001

• Preceding prime number: 822 989
• Following prime number: 823 003

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• 823 001 est-il un nombre premier ?