It is possible to find out using mathematical methods whether a given integer is a prime number or not.
For 83, the answer is: yes, 83 is a prime number because it has only two distinct divisors: 1 and itself (83).
As a consequence, 83 is only a multiple of 1 and 83..
Since 83 is a prime number, 83 is also a deficient number, that is to say 83 is a natural integer that is strictly larger than the sum of its proper divisors, i.e., the divisors of 83 without 83 itself (that is 1, by definition!).
Parity of 83
83 is an odd number, because it is not evenly divisible by 2.
Is 83 a perfect square number?
A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 83 is about 9.110.
Thus, the square root of 83 is not an integer, and therefore 83 is not a square number.
Anyway, 83 is a prime number, and a prime number cannot be a perfect square.
What is the square number of 83?
The square of a number (here 83) is the result of the product of this number (83) by itself (i.e., 83 × 83); the square of 83 is sometimes called "raising 83 to the power 2", or "83 squared".
As a consequence, 83 is the square root of 6 889.
Number of digits of 83
83 is a number with 2 digits.
What are the multiples of 83?
The multiples of 83 are all integers evenly divisible by 83, that is all numbers such that the remainder of the division by 83 is zero. There are infinitely many multiples of 83. The smallest multiples of 83 are:
- 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 83 too, since 0 × 83 = 0
- 83: indeed, 83 is a multiple of itself, since 83 is evenly divisible by 83 (we have 83 / 83 = 1, so the remainder of this division is indeed zero)
- 166: indeed, 166 = 83 × 2
- 249: indeed, 249 = 83 × 3
- 332: indeed, 332 = 83 × 4
- 415: indeed, 415 = 83 × 5
How to determine whether an integer is a prime number?
To determine the primality of a number, several algorithms can be used. The most naive technique is to test all divisors strictly smaller to the number of which we want to determine the primality (here 83). First, we can eliminate all even numbers greater than 2 (and hence 4, 6, 8…). Then, we can stop this check when we reach the square root of the number of which we want to determine the primality (here the square root is about 9.110). Historically, the sieve of Eratosthenes (dating from the Greek mathematics) implements this technique in a relatively efficient manner.
More modern techniques include the sieve of Atkin, probabilistic algorithms, and the cyclotomic AKS test.