It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 8 996 713 is not a prime number.
For example, 8 996 713 can be divided by 11: 8 996 713 / 11 = 817 883.
For 8 996 713 to be a prime number, it would have been required that 8 996 713 has only two divisors, i.e., itself and 1.
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8 996 713 is an odd number, because it is not evenly divisible by 2.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 8 996 713 is about 2 999.452.
Thus, the square root of 8 996 713 is not an integer, and therefore 8 996 713 is not a square number.
The square of a number (here 8 996 713) is the result of the product of this number (8 996 713) by itself (i.e., 8 996 713 × 8 996 713); the square of 8 996 713 is sometimes called "raising 8 996 713 to the power 2", or "8 996 713 squared".
The square of 8 996 713 is 80 940 844 804 369 because 8 996 713 × 8 996 713 = 8 996 7132 = 80 940 844 804 369.
As a consequence, 8 996 713 is the square root of 80 940 844 804 369.
The multiples of 8 996 713 are all integers evenly divisible by 8 996 713, that is all numbers such that the remainder of the division by 8 996 713 is zero. There are infinitely many multiples of 8 996 713. The smallest multiples of 8 996 713 are: