It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 8 997 263 is not a prime number.
For example, 8 997 263 can be divided by 11: 8 997 263 / 11 = 817 933.
For 8 997 263 to be a prime number, it would have been required that 8 997 263 has only two divisors, i.e., itself and 1.
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8 997 263 is an odd number, because it is not evenly divisible by 2.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 8 997 263 is about 2 999.544.
Thus, the square root of 8 997 263 is not an integer, and therefore 8 997 263 is not a square number.
The square of a number (here 8 997 263) is the result of the product of this number (8 997 263) by itself (i.e., 8 997 263 × 8 997 263); the square of 8 997 263 is sometimes called "raising 8 997 263 to the power 2", or "8 997 263 squared".
The square of 8 997 263 is 80 950 741 491 169 because 8 997 263 × 8 997 263 = 8 997 2632 = 80 950 741 491 169.
As a consequence, 8 997 263 is the square root of 80 950 741 491 169.
The multiples of 8 997 263 are all integers evenly divisible by 8 997 263, that is all numbers such that the remainder of the division by 8 997 263 is zero. There are infinitely many multiples of 8 997 263. The smallest multiples of 8 997 263 are: