It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 9 012 018 is not a prime number.
For example, 9 012 018 can be divided by 2: 9 012 018 / 2 = 4 506 009.
For 9 012 018 to be a prime number, it would have been required that 9 012 018 has only two divisors, i.e., itself and 1.
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9 012 018 is an even number, because it is evenly divisible by 2: 9 012 018 / 2 = 4 506 009.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 9 012 018 is about 3 002.002.
Thus, the square root of 9 012 018 is not an integer, and therefore 9 012 018 is not a square number.
The square of a number (here 9 012 018) is the result of the product of this number (9 012 018) by itself (i.e., 9 012 018 × 9 012 018); the square of 9 012 018 is sometimes called "raising 9 012 018 to the power 2", or "9 012 018 squared".
The square of 9 012 018 is 81 216 468 432 324 because 9 012 018 × 9 012 018 = 9 012 0182 = 81 216 468 432 324.
As a consequence, 9 012 018 is the square root of 81 216 468 432 324.
The multiples of 9 012 018 are all integers evenly divisible by 9 012 018, that is all numbers such that the remainder of the division by 9 012 018 is zero. There are infinitely many multiples of 9 012 018. The smallest multiples of 9 012 018 are: