It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 9 024 016 is not a prime number.
For example, 9 024 016 can be divided by 2: 9 024 016 / 2 = 4 512 008.
For 9 024 016 to be a prime number, it would have been required that 9 024 016 has only two divisors, i.e., itself and 1.
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9 024 016 is an even number, because it is evenly divisible by 2: 9 024 016 / 2 = 4 512 008.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 9 024 016 is 3 004.
Therefore, the square root of 9 024 016 is an integer, and as a consequence 9 024 016 is a perfect square.
The square of a number (here 9 024 016) is the result of the product of this number (9 024 016) by itself (i.e., 9 024 016 × 9 024 016); the square of 9 024 016 is sometimes called "raising 9 024 016 to the power 2", or "9 024 016 squared".
The square of 9 024 016 is 81 432 864 768 256 because 9 024 016 × 9 024 016 = 9 024 0162 = 81 432 864 768 256.
As a consequence, 9 024 016 is the square root of 81 432 864 768 256.
The multiples of 9 024 016 are all integers evenly divisible by 9 024 016, that is all numbers such that the remainder of the division by 9 024 016 is zero. There are infinitely many multiples of 9 024 016. The smallest multiples of 9 024 016 are: