# Is 9433 a prime number?

It is possible to find out using mathematical methods whether a given integer is a prime number or not.

Yes, 9 433 is a prime number.

Indeed, the definition of a prime numbers is to have exactly two distinct positive divisors, 1 and itself. A number is a divisor of another number when the remainder of Euclid’s division of the second one by the first one is zero. Concerning the number 9 433, the only two divisors are 1 and 9 433. Therefore 9 433 is a prime number.

As a consequence, 9 433 is only a multiple of 1 and 9 433.

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Since 9433 is a prime number, 9433 is also a deficient number, that is to say 9433 is a natural integer that is strictly larger than the sum of its proper divisors, i.e., the divisors of 9433 without 9433 itself (that is 1, by definition!).