It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 9 602 723 is not a prime number.
For example, 9 602 723 can be divided by 13: 9 602 723 / 13 = 738 671.
For 9 602 723 to be a prime number, it would have been required that 9 602 723 has only two divisors, i.e., itself and 1.
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9 602 723 is an odd number, because it is not evenly divisible by 2.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 9 602 723 is about 3 098.826.
Thus, the square root of 9 602 723 is not an integer, and therefore 9 602 723 is not a square number.
The square of a number (here 9 602 723) is the result of the product of this number (9 602 723) by itself (i.e., 9 602 723 × 9 602 723); the square of 9 602 723 is sometimes called "raising 9 602 723 to the power 2", or "9 602 723 squared".
The square of 9 602 723 is 92 212 289 014 729 because 9 602 723 × 9 602 723 = 9 602 7232 = 92 212 289 014 729.
As a consequence, 9 602 723 is the square root of 92 212 289 014 729.
The multiples of 9 602 723 are all integers evenly divisible by 9 602 723, that is all numbers such that the remainder of the division by 9 602 723 is zero. There are infinitely many multiples of 9 602 723. The smallest multiples of 9 602 723 are: