Is 980323 a prime number?

980 323 is an odd number, because it is not evenly divisible by 2.

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• What is an even number?

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 980 323 is about 990.113.

Thus, the square root of 980 323 is not an integer, and therefore 980 323 is not a square number.

The square of a number (here 980 323) is the result of the product of this number (980 323) by itself (i.e., 980 323 × 980 323); the square of 980 323 is sometimes called "raising 980 323 to the power 2", or "980 323 squared".

The square of 980 323 is 961 033 184 329 because 980 323 × 980 323 = 980 323² = 961 033 184 329.

As a consequence, 980 323 is the square root of 961 033 184 329.

980 323 is a number with 6 digits.

The multiples of 980 323 are all integers evenly divisible by 980 323, that is all numbers such that the remainder of the division by 980 323 is zero. There are infinitely many multiples of 980 323. The smallest multiples of 980 323 are:

• 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 980 323 too, since 0 × 980 323 = 0
• 980 323: indeed, 980 323 is a multiple of itself, since 980 323 is evenly divisible by 980 323 (we have 980 323 / 980 323 = 1, so the remainder of this division is indeed zero)
• 1 960 646: indeed, 1 960 646 = 980 323 × 2
• 2 940 969: indeed, 2 940 969 = 980 323 × 3
• 3 921 292: indeed, 3 921 292 = 980 323 × 4
• 4 901 615: indeed, 4 901 615 = 980 323 × 5
• etc.

• Preceding numbers: …980 321, 980 322
• Following numbers: 980 324, 980 325…

Nearest numbers from 980 323

• Preceding prime number: 980 321
• Following prime number: 980 327

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• 980 323 est-il un nombre premier ?