It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 980 982 is not a prime number.
For example, 980 982 can be divided by 2: 980 982 / 2 = 490 491.
For 980 982 to be a prime number, it would have been required that 980 982 has only two divisors, i.e., itself and 1.
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980 982 is an even number, because it is evenly divisible by 2: 980 982 / 2 = 490 491.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 980 982 is about 990.445.
Thus, the square root of 980 982 is not an integer, and therefore 980 982 is not a square number.
The square of a number (here 980 982) is the result of the product of this number (980 982) by itself (i.e., 980 982 × 980 982); the square of 980 982 is sometimes called "raising 980 982 to the power 2", or "980 982 squared".
The square of 980 982 is 962 325 684 324 because 980 982 × 980 982 = 980 9822 = 962 325 684 324.
As a consequence, 980 982 is the square root of 962 325 684 324.
The multiples of 980 982 are all integers evenly divisible by 980 982, that is all numbers such that the remainder of the division by 980 982 is zero. There are infinitely many multiples of 980 982. The smallest multiples of 980 982 are: