It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 988 081 012 is not a prime number.
For example, 988 081 012 can be divided by 2: 988 081 012 / 2 = 494 040 506.
For 988 081 012 to be a prime number, it would have been required that 988 081 012 has only two divisors, i.e., itself and 1.
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988 081 012 is an even number, because it is evenly divisible by 2: 988 081 012 / 2 = 494 040 506.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 988 081 012 is about 31 433.756.
Thus, the square root of 988 081 012 is not an integer, and therefore 988 081 012 is not a square number.
The square of a number (here 988 081 012) is the result of the product of this number (988 081 012) by itself (i.e., 988 081 012 × 988 081 012); the square of 988 081 012 is sometimes called "raising 988 081 012 to the power 2", or "988 081 012 squared".
The square of 988 081 012 is 976 304 086 274 944 128 because 988 081 012 × 988 081 012 = 988 081 0122 = 976 304 086 274 944 128.
As a consequence, 988 081 012 is the square root of 976 304 086 274 944 128.
988 081 012 is a number with 9 digits.
The multiples of 988 081 012 are all integers evenly divisible by 988 081 012, that is all numbers such that the remainder of the division by 988 081 012 is zero. There are infinitely many multiples of 988 081 012. The smallest multiples of 988 081 012 are: