It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 988 993 is not a prime number.
For example, 988 993 can be divided by 31: 988 993 / 31 = 31 903.
For 988 993 to be a prime number, it would have been required that 988 993 has only two divisors, i.e., itself and 1.
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988 993 is an odd number, because it is not evenly divisible by 2.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 988 993 is about 994.481.
Thus, the square root of 988 993 is not an integer, and therefore 988 993 is not a square number.
The square of a number (here 988 993) is the result of the product of this number (988 993) by itself (i.e., 988 993 × 988 993); the square of 988 993 is sometimes called "raising 988 993 to the power 2", or "988 993 squared".
The square of 988 993 is 978 107 154 049 because 988 993 × 988 993 = 988 9932 = 978 107 154 049.
As a consequence, 988 993 is the square root of 978 107 154 049.
The multiples of 988 993 are all integers evenly divisible by 988 993, that is all numbers such that the remainder of the division by 988 993 is zero. There are infinitely many multiples of 988 993. The smallest multiples of 988 993 are: