It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 989 498 is not a prime number.
For example, 989 498 can be divided by 2: 989 498 / 2 = 494 749.
For 989 498 to be a prime number, it would have been required that 989 498 has only two divisors, i.e., itself and 1.
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989 498 is an even number, because it is evenly divisible by 2: 989 498 / 2 = 494 749.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 989 498 is about 994.735.
Thus, the square root of 989 498 is not an integer, and therefore 989 498 is not a square number.
The square of a number (here 989 498) is the result of the product of this number (989 498) by itself (i.e., 989 498 × 989 498); the square of 989 498 is sometimes called "raising 989 498 to the power 2", or "989 498 squared".
The square of 989 498 is 979 106 292 004 because 989 498 × 989 498 = 989 4982 = 979 106 292 004.
As a consequence, 989 498 is the square root of 979 106 292 004.
The multiples of 989 498 are all integers evenly divisible by 989 498, that is all numbers such that the remainder of the division by 989 498 is zero. There are infinitely many multiples of 989 498. The smallest multiples of 989 498 are: