It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 9 920 623 is not a prime number.
For example, 9 920 623 can be divided by 67: 9 920 623 / 67 = 148 069.
For 9 920 623 to be a prime number, it would have been required that 9 920 623 has only two divisors, i.e., itself and 1.
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9 920 623 is an odd number, because it is not evenly divisible by 2.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 9 920 623 is about 3 149.702.
Thus, the square root of 9 920 623 is not an integer, and therefore 9 920 623 is not a square number.
The square of a number (here 9 920 623) is the result of the product of this number (9 920 623) by itself (i.e., 9 920 623 × 9 920 623); the square of 9 920 623 is sometimes called "raising 9 920 623 to the power 2", or "9 920 623 squared".
The square of 9 920 623 is 98 418 760 708 129 because 9 920 623 × 9 920 623 = 9 920 6232 = 98 418 760 708 129.
As a consequence, 9 920 623 is the square root of 98 418 760 708 129.
The multiples of 9 920 623 are all integers evenly divisible by 9 920 623, that is all numbers such that the remainder of the division by 9 920 623 is zero. There are infinitely many multiples of 9 920 623. The smallest multiples of 9 920 623 are: