Is 996993 a prime number?

996 993 is an odd number, because it is not evenly divisible by 2.

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• What is an even number?

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 996 993 is about 998.495.

Thus, the square root of 996 993 is not an integer, and therefore 996 993 is not a square number.

The square of a number (here 996 993) is the result of the product of this number (996 993) by itself (i.e., 996 993 × 996 993); the square of 996 993 is sometimes called "raising 996 993 to the power 2", or "996 993 squared".

The square of 996 993 is 993 995 042 049 because 996 993 × 996 993 = 996 993² = 993 995 042 049.

As a consequence, 996 993 is the square root of 993 995 042 049.

996 993 is a number with 6 digits.

The multiples of 996 993 are all integers evenly divisible by 996 993, that is all numbers such that the remainder of the division by 996 993 is zero. There are infinitely many multiples of 996 993. The smallest multiples of 996 993 are:

• 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 996 993 too, since 0 × 996 993 = 0
• 996 993: indeed, 996 993 is a multiple of itself, since 996 993 is evenly divisible by 996 993 (we have 996 993 / 996 993 = 1, so the remainder of this division is indeed zero)
• 1 993 986: indeed, 1 993 986 = 996 993 × 2
• 2 990 979: indeed, 2 990 979 = 996 993 × 3
• 3 987 972: indeed, 3 987 972 = 996 993 × 4
• 4 984 965: indeed, 4 984 965 = 996 993 × 5
• etc.

• Preceding numbers: …996 991, 996 992
• Following numbers: 996 994, 996 995…

Nearest numbers from 996 993

• Preceding prime number: 996 979
• Following prime number: 997 001

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• 996 993 est-il un nombre premier ?