It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 997 992 is not a prime number.
For example, 997 992 can be divided by 2: 997 992 / 2 = 498 996.
For 997 992 to be a prime number, it would have been required that 997 992 has only two divisors, i.e., itself and 1.
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997 992 is an even number, because it is evenly divisible by 2: 997 992 / 2 = 498 996.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 997 992 is about 998.995.
Thus, the square root of 997 992 is not an integer, and therefore 997 992 is not a square number.
The square of a number (here 997 992) is the result of the product of this number (997 992) by itself (i.e., 997 992 × 997 992); the square of 997 992 is sometimes called "raising 997 992 to the power 2", or "997 992 squared".
The square of 997 992 is 995 988 032 064 because 997 992 × 997 992 = 997 9922 = 995 988 032 064.
As a consequence, 997 992 is the square root of 995 988 032 064.
The multiples of 997 992 are all integers evenly divisible by 997 992, that is all numbers such that the remainder of the division by 997 992 is zero. There are infinitely many multiples of 997 992. The smallest multiples of 997 992 are: