It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 9 997 117 is not a prime number.
For example, 9 997 117 can be divided by 13: 9 997 117 / 13 = 769 009.
For 9 997 117 to be a prime number, it would have been required that 9 997 117 has only two divisors, i.e., itself and 1.
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9 997 117 is an odd number, because it is not evenly divisible by 2.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 9 997 117 is about 3 161.822.
Thus, the square root of 9 997 117 is not an integer, and therefore 9 997 117 is not a square number.
The square of a number (here 9 997 117) is the result of the product of this number (9 997 117) by itself (i.e., 9 997 117 × 9 997 117); the square of 9 997 117 is sometimes called "raising 9 997 117 to the power 2", or "9 997 117 squared".
The square of 9 997 117 is 99 942 348 311 689 because 9 997 117 × 9 997 117 = 9 997 1172 = 99 942 348 311 689.
As a consequence, 9 997 117 is the square root of 99 942 348 311 689.
The multiples of 9 997 117 are all integers evenly divisible by 9 997 117, that is all numbers such that the remainder of the division by 9 997 117 is zero. There are infinitely many multiples of 9 997 117. The smallest multiples of 9 997 117 are: