Is 1999 a prime number? What are the divisors of 1999?

## Is 1999 a prime number?

Yes, 1999 is a prime number.

Indeed, the definition of a prime numbers is to have only two distinct positive divisors, 1 and itself. A number is a divisor of another number when the remainder of Euclid’s division of the second one by the first one is zero. Concerning the number 1999, the only two divisors are 1 and 1999. Therefore 1999 is a prime number.

As a consequence, 1999 is only a multiple of 1 and 1999.

Therefore year 1999 was a prime year.

Since 1999 is a prime number, 1999 is also a deficient number, that is to say 1999 is a natural integer that is strictly larger than the sum of its proper divisors, i.e., the divisors of 1999 without 1999 itself (that is 1, by definition!).

## Parity of 1999

1999 is an odd number, because it is not evenly divisible by 2.

## Is 1999 a perfect square number?

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 1999 is about 44.710.

Thus, the square root of 1999 is not an integer, and therefore 1999 is not a square number.

Anyway, 1999 is a prime number, and a prime number cannot be a perfect square.

## What is the square number of 1999?

The square of a number (here 1999) is the result of the product of this number (1999) by itself (i.e., 1999 × 1999); the square of 1999 is sometimes called "raising 1999 to the power 2", or "1999 squared".

The square of 1999 is 3 996 001 because 1999 × 1999 = 19992 = 3 996 001.

As a consequence, 1999 is the square root of 3 996 001.

## Number of digits of 1999

1999 is a number with 4 digits.

## What are the multiples of 1999?

The multiples of 1999 are all integers evenly divisible by 1999, that is all numbers such that the remainder of the division by 1999 is zero. There are infinitely many multiples of 1999. The smallest multiples of 1999 are:

• 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 1999 too, since 0 × 1999 = 0
• 1999: indeed, 1999 is a multiple of itself, since 1999 is evenly divisible by 1999 (we have 1999 / 1999 = 1, so the remainder of this division is indeed zero)
• 3 998: indeed, 3 998 = 1999 × 2
• 5 997: indeed, 5 997 = 1999 × 3
• 7 996: indeed, 7 996 = 1999 × 4
• 9 995: indeed, 9 995 = 1999 × 5
• etc.

## Nearest numbers from 1999

Find out whether some integer is a prime number